Cum simplificați (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5)?

Răspuns:

# (3x + 2) / (3x + 1) #

Explicaţie:

Factorul termenilor:

# (3x ^ 2 + 14x + 8) / (2x ^ 2 +-7x 4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5) = #

# ((3x + 2) (x + 4)) / ((2x-1) (x + 4)) * ((2x-1) (x + 5)) / ((3x + 1) (x + 5)) #

Anulați termenii identici constatați în factorizare:

# ((3x + 2) (x + 4)) / ((2x-1) (x + 4)) * ((2x-1) (x + 5)) / ((3x + 1) (x + 5)) = #

# (3x + 2) / (3x + 1) #